Differentiating a complex power series

Click For Summary
The discussion revolves around differentiating a complex power series represented by f(z) = Σ(z^n) from 0 to infinity. The user seeks clarification on substituting different forms of f'(z) into an ordinary differential equation (ODE) zf'(z) + af(z) = f'(z). It is confirmed that substituting the derived equations for f'(z) is appropriate and not considered cheating, as it maintains the integrity of the series. The importance of including constants in the series representation is also emphasized. The user is encouraged to proceed with their approach.
Pyroadept
Messages
82
Reaction score
0

Homework Statement




Say f(z) = Σ(z^n), with sum from 0 to infinity

Then we can say f'(z) = Σn(z^n-1), with sum from 0 to infinity (i)

= Σn(z^n-1), with sum from 1 to infinity (as the zero-th term is 0)

= Σ(n+1)(z^n), with sum from 0 to infinity (ii)




Homework Equations





The Attempt at a Solution


Hi,

I am solving an ODE using power series, zf'(z) + af(z) = f'(z), so is it ok for me to sub in eq. (i) for the first f'(z) and eq. (ii) for the second? (This way all the terms will contain a z^n. Or is this cheating? If so, what can I do instead?)

Thanks for any help
 
Physics news on Phys.org
Well, no. You aren't cheating. That seems like the right way to shift the sum. Carry on.
 
Don't forget the constants in the sum, f(z) = \sum a_n z^n
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
8
Views
2K
Replies
12
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
13
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K