Differentiating a complex power series

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SUMMARY

The discussion focuses on differentiating the power series f(z) = Σ(z^n) and its implications in solving ordinary differential equations (ODEs). The user inquires about substituting derived equations for f'(z) into their ODE, specifically using the forms f'(z) = Σn(z^n-1) and f'(z) = Σ(n+1)(z^n). The consensus is that this substitution is valid and not considered cheating, as it maintains the integrity of the series representation. The importance of including constants in the series is also emphasized.

PREREQUISITES
  • Understanding of power series and their convergence
  • Familiarity with ordinary differential equations (ODEs)
  • Knowledge of differentiation techniques for series
  • Basic grasp of summation notation and manipulation
NEXT STEPS
  • Study the properties of power series convergence
  • Learn about the method of solving ODEs using power series
  • Explore the concept of term-by-term differentiation of series
  • Investigate the role of constants in series solutions
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Students and educators in mathematics, particularly those focusing on calculus and differential equations, as well as anyone interested in the application of power series in solving ODEs.

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Homework Statement




Say f(z) = Σ(z^n), with sum from 0 to infinity

Then we can say f'(z) = Σn(z^n-1), with sum from 0 to infinity (i)

= Σn(z^n-1), with sum from 1 to infinity (as the zero-th term is 0)

= Σ(n+1)(z^n), with sum from 0 to infinity (ii)




Homework Equations





The Attempt at a Solution


Hi,

I am solving an ODE using power series, zf'(z) + af(z) = f'(z), so is it ok for me to sub in eq. (i) for the first f'(z) and eq. (ii) for the second? (This way all the terms will contain a z^n. Or is this cheating? If so, what can I do instead?)

Thanks for any help
 
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Well, no. You aren't cheating. That seems like the right way to shift the sum. Carry on.
 
Don't forget the constants in the sum, [tex]f(z) = \sum a_n z^n[/tex]
 

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