Differentiating lnsecx: -pi/2 <= x <= 0

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SUMMARY

The discussion focuses on differentiating the function y = ln(sec(x)) within the interval -π/2 ≤ x ≤ 0. Participants suggest using the substitution u = sec(x) to simplify the differentiation process. The correct derivative, dy/dx, is derived using the chain rule, resulting in dy/dx = tan(x). The conversation emphasizes the importance of applying the chain rule correctly and providing hints rather than complete solutions in educational settings.

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Homework Statement


Given that y = lnsecx, - pi/2 <=x<=0, use the substituation u = secx, or otherwise, to show that dy/dx = tan x.

The Attempt at a Solution



well i thought about using the product rule, but you as it's ln(secx) not lnxsecx (2 different functions)... soooo I am all out of ideas :(

Thanks :)
 
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You could probably use chain rule...as in:

<< complete solution deleted by berkeman >>

Don't quote me on this, I'm still learning basic calculus.=D
 
Last edited by a moderator:
DMac said:
You could probably use chain rule...

DMac,

FYI, it's preferable to just give hints, like the part I quoted above, rather than give complete solutions as you did.

Regards,

Mark
 
Hi thomas49th! :smile:

The question says:
thomas49th said:
… use the substituation u = secx …

So try it … u = secx, so du = … ?, and y = … ? :smile:
 
chain rule:

dy/dx = dy/du . du/dx

dy/du of lnsecx = 1/secx

du/dx = secxtanx

1/secx . secxtanx = tanx

Cheers :)
 
Whoops sry guys, I'm still relatively new to the forum. My apologies.
 
DMac said:
Whoops sry guys, I'm still relatively new to the forum. My apologies.

urrh …I was asleep! :zzz:

Listen for the snoring next time!
 

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