Find the curvature of y=sec x.

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SUMMARY

The curvature of the function y=sec x is calculated using the formula k(x)=|y''|/[1+(y')^2]^(3/2). The first derivative is y'=sec x * tan x, and the second derivative is y"=sec x(sec^2 x + tan^2 x). The curvature expression simplifies to k(x)=|sec x(sec^2 x + tan^2 x)|/[1+(sec x * tan x)^2]^(3/2). The discussion highlights the complexity of simplification and references WolframAlpha for potential simplification suggestions.

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Homework Statement


Find the curvature of y=sec x.

Homework Equations


None.

The Attempt at a Solution


k(x)=abs(y")/[1+(y')^2]^(3/2)
y'=secx*tanx
y"=secx(sec^2 x+tan^2 x)
k(x)=abs(secx(sec^2 x+tan^2 x))/[1+(secx*tanx)^2]^(3/2)
how do I simplify this?
 
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Are you sure it can be simplified? WolframAlpha finds suggestions, but I don't think they are simpler.
 

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