Differentiating x(t): Solutions & Examples

  • Thread starter Thread starter JakePearson
  • Start date Start date
Click For Summary

Homework Help Overview

The discussion revolves around differentiating various functions of the form x(t) and includes a problem related to the volume of cylindrical containers and the height of a parachute above the ground. The subject area primarily involves calculus and applications of differentiation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants attempt to differentiate several functions, including polynomial and trigonometric forms. They raise questions about the correctness of each other's differentiation steps and the clarity of their work. Some participants express confusion about the proper format for presenting derivatives.

Discussion Status

There is ongoing feedback regarding the differentiation attempts, with some participants confirming the correctness of certain answers while questioning others. Guidance is provided on how to properly format the differentiation process, indicating a productive direction in clarifying the approach to the problems.

Contextual Notes

Some participants note that showing work is essential for full credit, and there are indications that assumptions about the completeness of answers may need to be revisited. Additionally, there is mention of specific homework requirements that may affect how solutions are presented.

JakePearson
Messages
52
Reaction score
0
1)
Differentiate x(t) = pi / t2
pi x(t) = t-2
= pi (t-2)
= -2pi t-3

2)
Differentiate x(t) = 1 / (At3 + B)
= (At3 + B)-2 x (2At2)
= (-2At2) / (At3 + B)

3)
Differentiate x(t) = [A sqrt(t+B)]4
= [A (t+B)1/2]4
= A4(t + B)2
= 2A4(t + B)

4)
The nebraska board of grain are designing new portable grain silos. they have enough sheet material to make 2000 cylinderical containers, each of fixed surface area 54m2 (this includesthe cylinder ends). calculate in terms of pi the maximum volume of grain that could be stored in total?

my answer is = for 1 container V is 30.46m3, so for 2000 containers (30.46 x 2000) = 60920m3 is this correct

5)
The height h(x) in meters above the ground of a parachute varies with her horizontal distance x in meters from a landing target on the ground as h(x) = 50sin-1 (0.1x). What is the rate of change of h with respect to x = 6m?

my answer is (25 / 4) is this correct
 
Physics news on Phys.org
HI JakePearson! :smile:

First, you must begin your proofs with "dx/dt =" (or "x'(t) = ").

(and have a pi: π and a square-root: √ :wink:)
JakePearson said:
1)
Differentiate x(t) = pi / t2
pi x(t) = t-2
= pi (t-2)
= -2pi t-3

ok (apart from "pi x(t) = t-2")
2)
Differentiate x(t) = 1 / (At3 + B)
= (At3 + B)-2 x (2At2)
= (-2At2) / (At3 + B)

No, 2At2 is wrong, and the last line is also wrong.
3)
Differentiate x(t) = [A sqrt(t+B)]4
= [A (t+B)1/2]4
= A4(t + B)2
= 2A4(t + B)

ok, except see my original comment.
4) …

5) …

uhh? :redface: show your calclulations!
 
1) is OK

2) is wrong ... I assume there is a - sign error of copying, since it appears later. But there is another error.

3) is OK

4) is at least incomplete. To tell if if it right I would have to do it myself (rather than checking that you have done it right.

5) correct answer, but if "showing work" is required it is incomplete
 
1)
Differentiate x(t) = pi / t2
pi x(t) = t-2
= pi (t-2)
= -2pi t-3
You arrived at the correct answer, but the work you show is incorrect. To expand on what tiny-tim said, your first line should be the function you're going to differentiate, and the second should start with dx/dt or x'(t).

Your second line is incorrect. Apparently you multiplied both sides by [itex]\pi[/itex] (which would leave [itex]\pi^2[/itex] on the right side. The expression in the third line is not equal to the previous line. What you omitted showing is that you took the derivative.

Here's how your work should look:
x(t) = [itex]\pi[/itex] / t2 = [itex]\pi[/itex] t-2
x'(t) = -2 [itex]\pi[/itex] t-3

It's very important to distinguish between the equation for the function you're differentiating and the equation for the derivative. If you mix them up into one big, amorphous glop, there will come a time -- I GUARANTEE IT--that it will come along and bite you in the butt.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
Replies
6
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
9K