Differentiating y: Product Rule Applied

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SUMMARY

The discussion focuses on differentiating the function y = u * e^t + v * t * e^t using the Product Rule. The correct application of the Product Rule is confirmed, stating that for functions x, y, and z of t, the derivative is d/dt [xyz] = x'yz + xy'z + xyz'. The participants clarify the differentiation process, ensuring that both u and v are treated as functions of t, leading to the correct derivative expression.

PREREQUISITES
  • Understanding of the Product Rule in calculus
  • Familiarity with differentiation of exponential functions
  • Knowledge of functions of a variable, specifically in relation to t
  • Basic algebraic manipulation skills
NEXT STEPS
  • Review the Product Rule and its applications in calculus
  • Practice differentiating composite functions involving exponentials
  • Explore the Chain Rule for more complex function differentiation
  • Study examples of differentiating products of multiple functions
USEFUL FOR

Students studying calculus, particularly those learning about differentiation techniques, as well as educators looking for examples of applying the Product Rule in real-world scenarios.

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Homework Statement


Differentiate y = u * e^t + v * t * e^t


Homework Equations


Product Rule.


The Attempt at a Solution


y = u' * e^t + u * e^t + ( v' * t * e^t + v * e^t + v * t * e^t)

u and v are functions of t.

I forgot whether the product rule works like this: d/dt [xyz] = x'yz + xy'z + xyz' when x, y, z are all functions of t. Is this correct?
 
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Yes, that's correct.
 

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