1. The problem statement, all variables and given/known data Function f(x) = KxL K= 1.78 L= -1.39 Problem 1: Find f'(x). ____________________ v= 0.89 w= 0.5 "v" and "w" are two points located on the x-axis. Problem 2: Calculate f'(v). ____________________ Problem 3: Find the equation of the tangent line of f(x) over the point "w". The equation should be in this form y=Ax+B ____________________ Problem 1:This is how I worked out the differentiation: f(x) = e(ln 1.78)x-1.39 Setting u=x-1.39, f'(x) = (Ku)'(u) * u' (Ku)'(u) = (eu ln K)' = ln K * eu ln K = ln K * Ku u' = LxL-1 = -1.39x-2.39 So, f'(x) = ln 1.78(1.78x-1.39) * -1.39x-2.39 Is this correct? Regarding the other problems, do I need f'(x) to solve these? I don't know where to start.