Differentiation of a function with respect to itself

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SUMMARY

The discussion centers on the differentiation of the feedback factor \( K_f \) in amplifier circuits with respect to the variable \( K \). The equation \( K_f = \frac{K}{1 - \beta K} \) is derived using the quotient rule, resulting in \( \frac{dK_f}{dK} = \frac{1}{(1 - \beta K)^2} \). The key insight is that \( \frac{dK_f}{K_f} \) is expressed as a ratio of differentials, specifically \( \frac{dK_f}{K_f} = \frac{dK}{K(1 - \beta K)} \). This method clarifies the relationship between \( K_f \) and \( K \) in feedback systems.

PREREQUISITES
  • Understanding of calculus, specifically differentiation techniques.
  • Familiarity with the quotient rule in calculus.
  • Basic knowledge of feedback systems in electronics.
  • Concept of differential equations and their applications in engineering.
NEXT STEPS
  • Study the application of the quotient rule in various mathematical contexts.
  • Explore feedback control systems and their stability analysis.
  • Learn about differential equations in electrical engineering applications.
  • Investigate the role of \( \beta \) in amplifier feedback configurations.
USEFUL FOR

Electronics students, engineers working with amplifier circuits, and anyone interested in the mathematical foundations of feedback systems in control theory.

bitrex
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In one of my electronics textbooks I have the following equation related to feedback in amplifiers:

[tex]K_f = \frac{K}{1-K\beta}[/tex]

[tex]\frac{dK_f}{K_f} = \frac{1}{1-K\beta}\frac{dK}{K}[/tex]

I'm not sure how this was derived - how was Kf differentiated with respect to itself?
 
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[itex]K_f[/itex] wasn't differentiated with respect to itself, it was differentiated with repect to [itex]K[/itex]. Here's what they did . . .

[tex]K_f = \frac{K}{1 - \beta K}[/tex]

[tex]\frac{\mathrm{d}K_f}{\mathrm{d}K} = \frac{(1 - \beta K) + (\beta K)}{(1 - \beta K)^2}[/tex]

[tex]\frac{\mathrm{d}K_f}{\mathrm{d}K} = \frac{1}{(1 - \beta K)^2}[/tex]

[tex]\frac{\mathrm{d}K_f}{K_f} = \frac{\mathrm{d}K}{K(1 - \beta K)}[/tex]

Basically, it's just an application of the quotient rule for differentiation.
 
Ah, I see now. They took the derivative of Kf with respect to K, and then expressed that derivative as a ratio to get dKf/Kf. Thank you!
 

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