- #1
Baartzy89
- 16
- 0
Hi,
Just a question on an example in a maths textbook. See attached image for question below.
So, I understand that if you set u=sin(x) and v=e^-cos(x)
f'(x)=u'.v + u.v'
But I'm stuck looking at e^-cos(x), could it also be classified e^(w)?
Also, the second step in differentiating the above equation seems to only differentiate the -cos(x) of the e^-cos(x)...is this because the derivative of e is simply e?
Just a question on an example in a maths textbook. See attached image for question below.
So, I understand that if you set u=sin(x) and v=e^-cos(x)
f'(x)=u'.v + u.v'
But I'm stuck looking at e^-cos(x), could it also be classified e^(w)?
Also, the second step in differentiating the above equation seems to only differentiate the -cos(x) of the e^-cos(x)...is this because the derivative of e is simply e?