- #1

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Hi,

Just a question on an example in a maths textbook. See attached image for question below.

So, I understand that if you set u=sin(x) and v=e^-cos(x)

f'(x)=u'.v + u.v'

But I'm stuck looking at e^-cos(x), could it also be classified e^(w)?

Also, the second step in differentiating the above equation seems to only differentiate the -cos(x) of the e^-cos(x)...is this because the derivative of e is simply e?

Just a question on an example in a maths textbook. See attached image for question below.

So, I understand that if you set u=sin(x) and v=e^-cos(x)

f'(x)=u'.v + u.v'

But I'm stuck looking at e^-cos(x), could it also be classified e^(w)?

Also, the second step in differentiating the above equation seems to only differentiate the -cos(x) of the e^-cos(x)...is this because the derivative of e is simply e?