Difficult Question on Permutations

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    Permutations
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Discussion Overview

The discussion revolves around determining the minimum positive integer k such that a given permutation, expressed in disjoint cycle notation, raised to the power of k equals the identity permutation. The scope includes theoretical reasoning about permutations and their properties.

Discussion Character

  • Exploratory, Technical explanation, Conceptual clarification

Main Points Raised

  • One participant asks for the minimum positive integer k such that t^k equals the identity, where t is a permutation in disjoint cycle notation.
  • Another participant prompts reasoning about the effects of multiplying the permutation τ by itself and suggests exploring τ^3 to understand the general behavior of repeated multiplication.
  • A third participant notes that disjoint cycles commute, stating that if τ is a product of disjoint cycles, then τ^n can be expressed as the product of each cycle raised to the power of n.
  • A later reply expresses a desire for a specific participant to arrive at the conclusion independently, indicating a preference for self-discovery in the reasoning process.

Areas of Agreement / Disagreement

Participants present various perspectives on the properties of permutations and their powers, but there is no consensus on the specific value of k or the implications of the multiplication of τ.

Contextual Notes

The discussion does not clarify certain assumptions about the structure of the permutation or the specific cycles involved, which may affect the determination of k.

Who May Find This Useful

Individuals interested in combinatorial mathematics, particularly those studying permutations and their properties in abstract algebra.

PhysicsHelp12
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If you have a permutation writtein disjoint cycle notation ( I attatched it )

what's the minimum positive integer k such that t^k =Identity

t is tau
 

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Can you reason what will happen when \tau is multiplied by itself? And if you calculate \tau^3?
What will happen in general when we keep multiplying tau by itself?
 
Remember that disjoint cycles commute. Thus, if \tau = \tau_1 \tau_2 \dotsc \tau_m is a product of disjoint cycles, then \tau^n = \tau_1^n \tau_2^n \dotsc \tau_m^n.
 
Last edited:
Very well adrian, although I was sort of hoping PhysicsHelp12 would figure that out by himself.
 

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