Difficulty visualizing given set

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The discussion centers on visualizing a geometric set defined by a cone, sphere, and cylinder. Participants suggest using cylindrical coordinates for integration, with specific ranges for φ and z. There is a consensus that R should be a function of height for integration purposes. Various online tools, such as GeoGebra and Wolfram Alpha, are recommended for better visualization. Overall, the conversation emphasizes the importance of using available resources to aid understanding in geometry.
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Homework Statement
Hey,
As you can see in the attachment, I am given a Set that I should integrate a function on. The integrating part should not be a problem, however I am having a hard time figuring out how this set looks like and hence which coordinates to use. I get that the best option would probably be spherical coordinates, but I have to have an idea how this set looks like so I can determine the bounds of integration, that is bounds for φ, Θ and R.
Relevant Equations
Spherical coordinates: x=Rsin(Θ)cos(φ), y=Rsin(Θ)sin(φ), z=Rcos(Θ)
Okay so I know, that if the radius is 0, the z coordinate will run from -1 to +1. If the radius tends to one, the z coordinate will tend to 0.
But I still cannot imagine how this set looks like, help would be appreciated.

Thank you.
set.PNG
 
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This is the region between the cone x^2 + y^2 = (z + 1)^2 and the sphere x^2 + y^2 + z^2 = 1 and bounded by the cylinder x^2 + y^2 = 1.

I would suggest cylindrical polars.
 
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Thanks for your reply.
If I were to use cylindrical coordinates, then I assume I would let φ range from 0 to 2π, z from -1 to 1. But what about R then? R should be a function of the height regarding integration over the cone and then another function of height regarding integration over the sphere right?
 
Physicsdudee said:
Thanks for your reply.
If I were to use cylindrical coordinates, then I assume I would let φ range from 0 to 2π, z from -1 to 1. But what about R then? R should be a function of the height regarding integration over the cone and then another function of height regarding integration over the sphere right?

Easier to have 0 \leq r \leq 1, and the z limits are then conveniently set out in the question...
 
Yes, that seems easier, thanks a lot!
 
While it's good to try to reason on your own,
be aware that there are useful tools, as @fresh_42 suggests.

Here's another one

https://www.geogebra.org/3d?lang=en
1655490235679.png

1655490273881.png


I'm sure it can also handle spherical and cylindrical coordinates.
 
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robphy said:
While it's good to try to reason on your own,
be aware that there are useful tools, as @fresh_42 suggests.

Here's another one

https://www.geogebra.org/3d?lang=en
View attachment 302958
View attachment 302960

I'm sure it can also handle spherical and cylindrical coordinates.
Yep, I know Geo gebra but I was so eager to actually not use anything because in the exam it’s not going to be any different. But I get your point, making use of all these nice tools is extremely good for visualizing
 
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@Physicsdudee ,
I see that this is the second Thread you have started, but you have not received a formal welcome to Physics Forums. Let's fix that.

:welcome:
 
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SammyS said:
@Physicsdudee ,
I see that this is the second Thread you have started, but you have not received a formal welcome to Physics Forums. Let's fix that.

:welcome:
Haha that’s so kind, I appreciate it:)
 
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