Diffraction from a loud speaker

[pmd28]

Homework Statement

Sound exits a diffraction horn loudspeaker through a rectangular opening like a small doorway. Such a loudspeaker is mounted outside on a pole. In winter, when the temperature is 273 K, the diffraction angle θ has a value of 11°. What is the diffraction angle for the same sound on a summer day when the temperature is 307 K?

Homework Equations

v=sqrt(\gammakT/m)
v=\lambdaf
sin\theta=\lambda/D

The Attempt at a Solution

I can't seem to relate these equations. I know that \gammak/m is constant for both T and I also know that v increases with temperature but I don't understand how that affects lambda and frequency.

 

[TSny]

The frequency of a sound wave is determined by the frequency of vibration of the source of sound (the speaker in this case). So, changing the temperature does not change the frequency of the sound if you assume the speaker vibrates at the same frequency for both temperatures.

A good way to approach this problem is to consider the ratio \frac{sin\theta_f}{sin\theta_i} where the subscripts refer to the initial and final temperatures.

 

[pmd28]

So I set that ratio equal to the ratio of v_f/v_i and then canceled out sqrt(\gammak/m) because it is constant in both cases therefore the ratio of Sin_fθ/Sin_iθ is equal to sqrt(T_f)/sqrt(T_i) It was correct.