Diffraction Grating: Does Light Excite Electrons or Pass Through Holes?

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Incoming light interacts with a wire diffraction grating primarily through two mechanisms: it can either excite electrons in the metal, leading to scattering and the emission of new light, or it can pass through the holes in the mesh. The discussion highlights a common misconception regarding these processes, emphasizing that the path separations are crucial for the interference pattern observed in diffraction. While some interpretations suggest that the original light passes through the holes, others, including insights from the Feynman Lectures, propose that electron excitation is responsible for the emitted light that contributes to the diffraction pattern. Ultimately, both mechanisms are debated, but the interference effect is fundamentally linked to the path separations of the light. Understanding these interactions is essential for grasping the principles of diffraction grating.
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Simple question about this:

Say you have a wire diffraction grating. Does the incoming light excite the electrons in the metal, which scatter new light *or* does the incoming light simply pass through the "holes" in the mesh and get absorbed by the grating? I've seen it explained both ways, yet they seem incompatible.

Thanks!
 
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It is only the path separations which cause every photon to interfere with itself creating the diffraction you see.
 
jerromyjon said:
It is only the path separations which cause every photon to interfere with itself creating the diffraction you see.

I get that. I had always understood these gratings as allowing the "original" light to pass through the holes in them, then interfere with itself. However, I recently read (Feynman Lectures) that the light excites the elections in the metal grating, and that is what emits the light which forms the pattern.
 

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