Diffraction Gratings, confusing question.

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skg94
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Homework Statement



Perspective diagram of a student apparatus: a vertical low-pressure helium gas-discharge tube connected to a high-voltage power supply, clamped to a retort stand, with a diffraction grating and metre sticks set up in front of it.


Diagram of a diffraction grating experiment with a discharge tube, meter stick and screen, above a printed scale of spectral lines labelled Blue, Violet, Green, Yellow and Red.


Homework Equations



λ=xd/nl

The Attempt at a Solution



Im having some difficulty with the variables, is d= lines/m? and n= 27? from the 50 mark to the yellow mark. then x would be 27*(4.35*10^-6) and l would be 100cm=1m ?
 
d is the distance between lines at the grating.
n is the order of the line. As you have just one line for each color (0 would correspond to light directed towards the tube), it is 1.

then x would be 27*(4.35*10^-6)
That looks like xd, but it has no units and where does the value of 27 come from?

and l would be 100cm=1m ?
Right
 
Those are lines on the ruler, they are completely arbitrary (you could use a ruler with mm-marks as well). 13.5cm is the physical quantity, it does not depend on the type of ruler.
 
i just assumed that because of the each etched mark is 4.35*10^-6 apart, so d would be 4.35*10^-6 but x would be that times the 27 lines from the distance from central to the node.

So x =.135m d= 4.35*10^-6 l =1 and n= 1 so really the calculation is (.135*4.35*10^-6) ?