The generators of ##SO(n)## are pure imaginary antisymmetric ##n \times n## matrices.(adsbygoogle = window.adsbygoogle || []).push({});

How can this fact be used to show that the dimension of ##SO(n)## is ##\frac{n(n-1)}{2}##?

I know that an antisymmetric matrix has ##\frac{n(n-1)}{2}## degrees of freedom, but I can't take this idea any further in the demonstration of the proof.

Thoughts?

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# Dimension of SO(n) and its generators

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