Dimensional Analysis: Finding Relation Between v, p and p

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SUMMARY

The discussion focuses on using dimensional analysis to establish a relationship between the velocity of sound (v), density (ρ), and pressure (p) in a gas. The key equations provided are [v] = LT-1, [ρ] = ML-3, and [p] = ML-1T-2. The relationship is expressed as v = ρα · pβ, where α and β are to be determined through dimensional analysis, ensuring that both sides of the equation have matching dimensions.

PREREQUISITES
  • Understanding of dimensional analysis principles
  • Familiarity with physical quantities and their dimensions
  • Knowledge of basic algebra for manipulating equations
  • Concept of functions in physics
NEXT STEPS
  • Learn how to derive dimensional equations for various physical quantities
  • Study the application of dimensional analysis in fluid dynamics
  • Explore the concept of Buckingham π theorem for dimensional analysis
  • Investigate the relationship between pressure, density, and velocity in different gases
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Students in physics, particularly those studying fluid dynamics, as well as educators teaching dimensional analysis and its applications in real-world scenarios.

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Homework Statement


The velocity,v of the sound in a gas depends on the density, p and the pressure, p of the gas. By using dimensional analysis, find a possible relation between v, p and p.


Homework Equations


[v] = LT-1
[p] = ML-3
[p] = ML-1T-2


The Attempt at a Solution


well i have no idea how to do it, so far i can only express the variables in dimension ways
 
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Here, have a ρ to express the density.

The whole concept of dimensional analysis is based on the fact that you can only equate two quantities if they have the same dimensions and units.

You are told that the velocity of sound in a gas, [tex]v[/tex] depends on two factors, that is to say, that it is a function of these two factors.

[tex]v=f(\rho , p)[/tex]

Naively, we say that it is a product of these two quantities, raised to some powers [tex]\alpha, \beta[/tex]:

[tex]v=\rho^{\alpha}\cdot p^{\beta}[/tex]

Now use dimensional analysis to find [tex]\alpha, \beta[/tex]

Do this by constraining the system so that the dimensions on the RHS are the same as the dimensions on the LHS.
 

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