- #1
ulfy01
- 6
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Homework Statement
I'm trying to work out if the following is dimensionally correct. I think I'm getting stuck at the (x - x0)
Homework Equations
In this case v is velocity (L/T), a is acceleration (L/T²), and x represents displacement, which is a length (L)
The Attempt at a Solution
My attempt was such:
v² = v0² = (L/T)² or L²/T²
a = L/T²
(x - x0) confuses me. That would work out to (L - L), correct? So a(x - x0) = L/T²(L - L)
Don't (L - L) cancel out, leaving me just with L/T² which is NOT the same as L²/T²?
According to the sheet, this expression is supposed to be dimensionally correct. Any pointer appreciated.