Dimensional formula of distances in certain formulas

Click For Summary
The discussion centers on the dimensional formula for distances in universal gravitation and moment of inertia, questioning whether L^2 is appropriate for both cases. While L^2 represents the square of distance, in the context of gravitational force, it acts as a divisor, leading to L^-2. Participants clarify that dimensional formulas do not distinguish between physical entities, as different concepts can share the same dimensions. The confusion arises from interpreting these dimensions as indicative of area rather than distance. Ultimately, the focus remains on understanding that dimensional formulas capture relationships but do not define the nature of the quantities involved.
Mathivanan

Homework Statement


Dimensional formula for 'the square of the distance between two bodies' in universal gravitation and 'distance from the axis squared' in moment of inertia. Is L^2 is the dimensional formula for both the distances in the above two cases?

Homework Equations


F=Gm1m2/d^2; moment of inertia=mass*distance from the axis squared

The Attempt at a Solution

 
Physics news on Phys.org
Mathivanan said:
Is L^2 is the dimensional formula for both the distances in the above two cases?
Yes, except that in the gravitational case it acts as a divisor, so becomes L-2.
 
haruspex said:
Yes, except that in the gravitational case it acts as a divisor, so becomes L-2.
Thanks. However, I have one more doubt. The dimensional formula for area is also L^2. By definitions, in the above two formulas, they represent distances rather than area. The dimensional formulas mislead me.
 
Mathivanan said:
Thanks. However, I have one more doubt. The dimensional formula for area is also L^2. By definitions, in the above two formulas, they represent distances rather than area. The dimensional formulas mislead me.
The dimensional formulas only capture that aspect of an expression. They don't care whether the two distances represent an actual area or have some other relationship. E.g. surface tension can be thought of as energy per unit area or force per unit length. In some cases, quite different physical entities can have the same dimension: torque and energy are both force x distance; action and angular momentum are both ML2T-1. It doesn't catch all the distinctions you'd like to make.
 
haruspex said:
The dimensional formulas only capture that aspect of an expression. They don't care whether the two distances represent an actual area or have some other relationship. E.g. surface tension can be thought of as energy per unit area or force per unit length. In some cases, quite different physical entities can have the same dimension: torque and energy are both force x distance; action and angular momentum are both ML2T-1. It doesn't catch all the distinctions you'd like to make.
Thanks for your answer. I thought that distance should have dimensional formula of L, be it square of the distance or distance from the axis squared. The core concept in the definition is distance in both the formulas.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
335
Views
16K
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
527
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 21 ·
Replies
21
Views
2K
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K