Dimensions of a room to be electrically heated

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SUMMARY

The discussion focuses on calculating the power rating of an electric heater required to maintain a room temperature of 20°C when the outside temperature is 0°C. The room dimensions are 7m x 6m x 3m, with two windows and a sliding glass door affecting heat loss. The total heat loss calculation, including the areas and transmission coefficients for the floor, walls, windows, and ceiling, results in a total heat loss of 68.64 m² for the walls, which requires clarification on the calculation method, particularly regarding the subtraction of window and door areas.

PREREQUISITES
  • Understanding of thermal transmission coefficients (U-values)
  • Basic knowledge of heat loss calculations
  • Familiarity with room dimensions and area calculations
  • Ability to create and interpret data tables
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  • Learn how to calculate heat loss using U-values and area
  • Research methods for calculating wall area while accounting for windows and doors
  • Explore electric heater power rating calculations based on heat loss
  • Investigate insulation materials and their impact on energy efficiency
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Engineers, architects, HVAC professionals, and anyone involved in building design or energy efficiency assessments will benefit from this discussion.

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A room 7m x 6m x 3m high is to be electically heated to maintain the inside temperature at 20 C, when it is 0 C outside. The room has 2 windows each 1.2m x 1.8m and a sliding glass door 2.4m x 2.1m. The transmission coefficients u in Wm^2/C are given below.

Floor: concrete slab (100mm thick) : 11.5 W/m^2/C

Walls: Cavity Brick (280mm thick) : 2.0 W/m^2/C

Windows and door (Single glazed) : 5.8 W/m^2/C

Ceiling: (do not consider a roof) : 1.0 W/m^2/C

Ignore the effects of furnishings, presence of humans, orientation to sun or any wind exposure

Assume:

There is no requirement to heat the air in the room

Calculate the power rating of the electric heater required to maintain the required temperature.
You are required to tabulate your calculations providing one row for each part of the buildings structure and column headings of area, u and heat loss. The total heat loss should be provided at the bottom of the table. Provide a table number and a suitable caption for your table.


-------------------------------

I've pretty much worked out the table.

However except for the area of the walls. The answer is coming to 68.64 m^2

I just don't know how they got that answer. Any light.

Cheers
 
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jase03 said:
A room 7m x 6m x 3m high is to be electically heated to maintain the inside temperature at 20 C, when it is 0 C outside. The room has 2 windows each 1.2m x 1.8m and a sliding glass door 2.4m x 2.1m. The transmission coefficients u in Wm^2/C are given below.

Floor: concrete slab (100mm thick) : 11.5 W/m^2/C

Walls: Cavity Brick (280mm thick) : 2.0 W/m^2/C

Windows and door (Single glazed) : 5.8 W/m^2/C

Ceiling: (do not consider a roof) : 1.0 W/m^2/C

Ignore the effects of furnishings, presence of humans, orientation to sun or any wind exposure

Assume:

There is no requirement to heat the air in the room

Calculate the power rating of the electric heater required to maintain the required temperature.
You are required to tabulate your calculations providing one row for each part of the buildings structure and column headings of area, u and heat loss. The total heat loss should be provided at the bottom of the table. Provide a table number and a suitable caption for your table.


-------------------------------

I've pretty much worked out the table.

However except for the area of the walls. The answer is coming to 68.64 m^2

I just don't know how they got that answer. Any light.
What's your method of calculating the area of the walls? Did you forget to subtract out the areas of the windows and door?
 

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