Dimensions related to Planck's constant H

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Homework Help Overview

The discussion revolves around dimensional analysis involving fundamental physical constants: the speed of light (C), Planck's constant (H), and the mass of the proton (M sub p). The original poster seeks to find combinations of these quantities that yield new dimensions of length (L) and time (T).

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to establish equations based on dimensional analysis to find the required combinations of C, H, and M sub p. They express their uncertainty and request a walkthrough of the solution process.

Discussion Status

Some participants have confirmed the original poster's findings, indicating that a productive direction has been established. However, there is no explicit consensus on the overall approach or final outcomes, as further questions about related topics have been raised.

Contextual Notes

The original poster mentions being new to physics and expresses a need for detailed guidance, which may influence the nature of the responses received.

ODBS
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Consider a system where the three fundamentally important quantities are the speed of light C with dimensions (L)/(T), Planck's constant H with dimensions (M)(L)^2/(T), and the mass of the proton M sub p with dimension (M).
a) What combination of ratios and/or products of C, H, and M sub p will yield a new quantity of dimensions (L)?
b) What combination of ratios and/or products of C, H, and M sub p will yield a new quantity of dimensions (T)?


I have no idea how to figure this out. I am brand new to physics so any help would be greatly appreciated. Could you please solve the question and walk me through how you found the answer? I am a very literal learner and I need to see the answer along with how you found it.




This is what I came up with, not sure if it's correct:

(C^a)*(H^b)*(M^c)

L^(a+2b)=L----> a+2b=1
M^(b+c)= 1-----> b+c=0
T^(a-b)=1---->a-b=0

a=-b
b=1
a=-1
c=-1

(C^-1)*(H^1)*(M^-1)=H/C*M

-a-b=1
a+2b=0
b+c=0
b=1
a=-2
c=-1

So, H/M*c*c


part A= H/M*C
part B= H/M*C*C
 
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:approve: yes, you are correct...I checked it myself. Cheers :smile:
 
Thank you! I've asked another question about fcc fraction packing for a pyramidal structure. Can you take a look at it and help me out? I'm really lost on that one.
 
ODBS said:
Thank you! I've asked another question about fcc fraction packing for a pyramidal structure. Can you take a look at it and help me out? I'm really lost on that one.

I would've if I myself had any clue!:-p I am a student myself, I am not proficient with that topic!...I am sure others will help out! :smile:
 

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