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Sure.paw said:Arrrrr, I missed that. They do tick at the same rate though, correct?
Sounds good.Thanks. Luckily I don't think any of that changes the results I predicted though.
1. Any time after C passes A, C will see both A and B ticking slower while A and B will see C ticking slower.
Sounds good. Assume that clocks A & B are a distance L apart (along the direction of motion) and are synchronized and that C passes A when both read t = 0. Then when C collides with B, B will read t = L/v and C will read [itex]L/(\gamma v)[/itex].2. A collision will occur.
3. B and C will not agree on the time the collision occurred.
(If I misunderstood the scenario, please correct me.)
Not sure what you mean. Proper time between what two events?4. After collision C will have accumulated more proper time than B.