Calculating AC and DC Resistance of a Silicon Diode in 300K

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SUMMARY

The discussion focuses on calculating the AC and DC resistances of a silicon diode at 300K, given a saturation current of 2µA and a forward current of 20mA. The AC resistance is determined to be 1.3 ohms through differentiation of the diode equation, while the DC resistance is calculated using the formula R(dc) = V(forward)/I(forward), yielding a value of approximately 11.97 ohms. Participants confirm the calculations and provide support in verifying the results.

PREREQUISITES
  • Understanding of diode equations, specifically the Shockley diode equation.
  • Knowledge of differentiation in the context of electrical engineering.
  • Familiarity with the concepts of AC and DC resistance.
  • Basic principles of semiconductor physics, particularly relating to silicon diodes.
NEXT STEPS
  • Learn about the Shockley diode equation and its applications in circuit analysis.
  • Study the effects of temperature on diode characteristics, particularly at 300K.
  • Explore methods for measuring forward voltage in diodes.
  • Investigate the impact of different materials on diode performance and resistance calculations.
USEFUL FOR

Electrical engineers, students studying semiconductor physics, and anyone involved in diode circuit design or analysis will benefit from this discussion.

rclakmal
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Diode ac and dc resistance?

here is my question ...saturation current of a silicon diode is 2uA.and forward current is 20mA...i want to find out the AC and DC resistances of the diode in 300k...

so i know that ,

I(forward)=I(saturate)[exp(eV/nKT)-1]

..so by differentiating both sides w.r.t to V i got that dI/dV=I(forward)*e/nkt...here KT/e=26mv so by subbing than (and also n=1 when conducting through diode)i got dV/dI=1.3ohms ...
so that is Ac resistance of the diode ...
but i don't know how to find the DC resistance of the diode can anyone help me out
 
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Are you sure that differentiation is right? doesn't look correct.
 


i think its correct ...what i have done is after differentiation i have subb i(forward) to the term I(saturation)*exp(ev/nKT)...and I am sure of that because i have done it before ...but i don't know how to calculate DC resistance ...DC(resistance)=V/I ...am i correct ...but i don't how to get a value for that ...
 


Yea sorry its correct. I thought doing that gave DC resistance not AC. Also do you know the foward voltage.
 


No i don't ,,,,,,,,,but after referring to some of my books i got some idea ...though i don't have the forward voltage i might be able to calculate it using forward and reverse currents by subbing them in the above equation then can get forward voltage ...

so i think DC(resistance)=V(forward)/I(forward)...
 


can someone check this answer for me ......here i forward is 20mA i saturated is 2uA and temp is 300k....i got the answer as R(dc)=11.9 ohms ...am i correct ?please someone check and tell me because in the MCQ question there is no such answer .....:(
 


I'll ask my teacher. That sounds a bit high though.
 


rclakmal said:
can someone check this answer for me ......here i forward is 20mA i saturated is 2uA and temp is 300k....i got the answer as R(dc)=11.9 ohms ...am i correct ?please someone check and tell me because in the MCQ question there is no such answer .....:(

I calculated 11.97 ohms which agrees well enough with your answer.
 


Thnaks dude !it was a great help!
 

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