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Zener diode : Calculating the series resistance

  1. Dec 24, 2015 #1
    1. The problem statement, all variables and given/known data :
    Given a voltage regulator with 6.8V Zener diode, input voltage range of 15-20V and load current range 5mA-20mA. Calculate the series resistance R for the regulator.


    2. Relevant equations :
    Applying KVL and no load situation, we get R = (V - Vz)/Iz where V is the input voltage,Vz is the zener voltage and Iz is the maximum current determined by the power dissipation.


    3. The attempt at a solution:
    At first glance , the question seems to be simple. However, looking at the given values, the problem seems to be more trickier. Maximum and minimum currents for Zener diode is not given in the problem. Let us solve by assuming the Zener diode as ideal where minimum current is zero.
    Izmax = (Vmax - Vz)/R - ILmin
    Izmin = (Vmin-Vz)/R - ILmax
    where Vmax = 20V, Vmin = 15V, ILmax = 20mA, ILmin=5mA and Vz = 6.8V
    These are the only equations which I can think of to solve this problem. Assuming Izmin = 0, I get R=410ohms which is not the right answer.
     
  2. jcsd
  3. Dec 24, 2015 #2

    NascentOxygen

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    :welcome:

    This formula doesn't look quite right. Can you explain what it is saying?

    What does your textbook give as their answer?

    http://www.imageshack.com/a/img109/4666/holly1756.gif [Broken]
     
    Last edited by a moderator: May 7, 2017
  4. Dec 24, 2015 #3
     

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    Last edited by a moderator: May 7, 2017
  5. Dec 24, 2015 #4

    CWatters

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    I also got 410R. Do you have one in your box of assorted resistors :-)
     
  6. Dec 24, 2015 #5

    NascentOxygen

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    I can't read pdfs (small tablet).

    410Ω looks okay, it's the upper bound.

    http://www.imageshack.com/a/img109/4666/holly1756.gif [Broken]
     
    Last edited by a moderator: May 7, 2017
  7. Dec 24, 2015 #6

    CWatters

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    In case it wasn't obvious this was a hint for why the answer might be 390 rather than 410.
     
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