Dipole of Magnetic field in polar coordinates

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SUMMARY

The discussion centers on deriving the spherical expressions for the magnetic field of a dipole, specifically when the magnetic moment \(\vec{m}\) is aligned with the z-axis. The magnetic field components are defined as \(B_r = \frac{\mu_0}{4 \pi} \frac{2 \cos \theta}{r^3}\) and \(B_\theta = \frac{\mu_0}{4 \pi} \frac{\sin \theta}{r^3}\). The user struggled with the scalar product and was advised to utilize spherical coordinates instead of cylindrical coordinates for the derivation.

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  • Proficiency in using scalar products in vector analysis.
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mahblah
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Homework Statement


Hi everybody... i have a bad problem with my brain:

starting from the Vectorial form of the magnetic dipole:

\vec{B}(\vec{r}) =\frac{\mu_0}{4 \pi} \frac{3 \vec{r} ( \vec{r} \cdot \vec{m}) - r^2 \vec{m}}{r^5}

Homework Equations



i want to derive the spherical expressions, with \vec{m} parallel with z axes

<br /> x = r \cos \theta; y = r \sin \theta; z=z<br />


The Attempt at a Solution



I don't know what to do... I've tried to write B_r = \sqrt{(B_x)^2 + (B_y)^2} ... but i fail...
the solution should be:

<br /> B_r = \frac{\mu_0}{4 \pi} \frac{2 \cos \theta}{r^3}<br />

<br /> B_\theta = \frac{\mu_0}{4 \pi} \frac{\sin \theta}{r^3}<br />


i don't know how to manage the scalar product, i feel really dumb and I am sorry for the low quality of my question,

just some general indication about what to do would be sufficient,

thank u so much.

mahblah.
 
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mahblah said:
<br /> x = r \cos \theta; y = r \sin \theta; z=z<br />

You should use spherical coordinates rather than cylindrical coordinates. See attached figure.

Note that ##B_r = \vec{B}\cdot\hat{r}## and ##B_\theta = \vec{B}\cdot\hat{\theta}##

So, you'll need to consider what you get from ##\vec{r}\cdot\hat{r}##, ##\vec{m}\cdot\hat{r}##, ##\vec{r}\cdot\hat{\theta}##, and ##\vec{m}\cdot\hat{\theta}##
 

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:)

Thank u so much TSny!
 

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