Dirac delta function with complex arguments

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The Dirac delta function can be extended to complex arguments, maintaining its fundamental property that the integral over a set is 1 if the argument is within that set. The discussion highlights that the delta function is a generalized function, not a true function, and can be defined for complex variables. When evaluating integrals involving the delta function with complex arguments, the expected results can become complex, particularly when applying the scaling property. The scaling property, which works well for real numbers, may lead to confusion when applied to complex scenarios, indicating a need for deeper understanding. Clarification on the derivation of the scaling property in the context of complex variables is sought.
JayFsd
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This is probably a silly question to some, but I've been struggling to understand how the delta function behaves when given a complex argument, that is \delta(z), z \in C. I guess the basic definition is the same that the integral over all space is 1, but I'm looking for a more detailed guide on the inner workings. Does someone know of a good reference?

TIA.
 
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The (Dirac) delta function, which is a "Distribution" or "Generalized Function", rather than a true "function", can be defined in a number of ways. The most common definition is that
\int_C f(x)\delta (x)dx
is equal to 1 if 0 is in set C, equal to 0 if 0 is not in set C.

More generally
\int_C f(x)\delta (x-a) dx[/itex]<br /> is equal to 1 if a is in set C, equal to 0 if 0 is not in set C.<br /> <br /> There is no reason C cannot be a subset of the complex numbers and a a complex number.<br /> <br /> It can be thought of, roughly, as the limit of a sequence of functions, f<sub>n</sub>, such that f<sub>n</sub>= n if |z|&lt; 1/n, 0 other wise. Of course, that sequence doesn&#039;t actually converge which is why \delta(z) is not a true function!
 
I kind of have a follow-up question to JayFsd (a year later, ha).

Suppose that a is complex and you have the integral

\int_C f\left(x\right) \delta\left(x - a\right)dx

such that a lies on the countour C, you would expect the result to be:

\int_C f\left(x\right) \delta\left(x - a\right)dx = f\left(a\right).

However, to evaluate this integral for a specific contour, let's say, we do the substitution x = x\left(t\right),\, 0 &lt;t &lt; 1 and get

\int_0^1 f\left(x\left(t\right)\right)\delta\left(x\left(t\right) - x\left(t_a\right)\right)\frac{dx}{dt}dt

where x\left(t_a\right) = a

Ok, so the question I have:

According to Wikipedia, the dirac delta scales as

\delta\left(g\left(x\right)\right) = \sum_i\frac{\delta\left(x - x_i\right)}{|g&#039;\left(x_i\right)}

where the x_i are the roots of g.

So if I use that scaling property in the above integral, then I get

\int_0^1 f\left(x\left(t\right)\right)\delta\left(x\left(t\right) - x\left(t_a\right)\right)\frac{dx}{dt}dt = \frac{dx}{dt_a}/\left|\frac{dx}{dt_a}\right|f\left(x\left(t_a\right)\right)

which doesn't agree with the expected result. It seems as if I don't understand the derivation of the scaling property well enough -- that is with real numbers it seems fine, but when you throw complex numbers in the mix I get hopelessly lost.

Anyone care to chime in and help me?
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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