Dirac Principle Value Identity applied to Propagators

Click For Summary

Discussion Overview

The discussion revolves around the application of the Dirac principle value identity to propagators in quantum field theory, specifically addressing an equation from Itzykson and Zuber. Participants explore the mathematical manipulation of propagators involving the Dirac operator and the implications of the identity in the context of the equation.

Discussion Character

  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant questions how the equation involving the Dirac operator and the imaginary epsilon term leads to a specific delta function identity, expressing confusion over the derivation.
  • Another participant suggests that the matrix nature of the Dirac operator necessitates a specific form of manipulation, indicating that the expression can be rewritten to facilitate the application of the delta function.
  • The same participant provides a detailed step-by-step breakdown of the manipulation, showing how the terms relate to each other and leading to the appearance of the delta function in the final expression.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the initial confusion regarding the equation, but one participant's explanation seems to clarify the derivation for another, indicating some level of agreement on the mathematical approach.

Contextual Notes

The discussion includes assumptions about the properties of the Dirac operator and the treatment of the epsilon term, which may not be universally accepted or fully explored. The steps provided rely on specific mathematical identities that may require further validation.

maverick280857
Messages
1,774
Reaction score
5
Hi,

How is

[tex]\frac{1}{\displaystyle{\not}{P}-m+i\epsilon}-\frac{1}{\displaystyle{\not}{P}-m-i\epsilon} = \frac{2\pi}{i}(\displaystyle{\not}{P}+m)\delta(P^2-m^2)[/tex]

? This is equation (4-91) of Itzykson and Zuber (page 189). I know that

[tex]\frac{1}{x\mp i\epsilon} = \mathcal{P}\left(\frac{1}{x}\right) \pm i\pi\delta(x)[/tex]

But this doesn't seem to give the right hand side of the first equation above. What am I missing?

Thanks in advance!
 
Physics news on Phys.org
maverick280857 said:
Hi,

How is

[tex]\frac{1}{\displaystyle{\not}{P}-m+i\epsilon}-\frac{1}{\displaystyle{\not}{P}-m-i\epsilon} = \frac{2\pi}{i}(\displaystyle{\not}{P}+m)\delta(P^2-m^2)[/tex]

? This is equation (4-91) of Itzykson and Zuber (page 189). I know that

[tex]\frac{1}{x\mp i\epsilon} = \mathcal{P}\left(\frac{1}{x}\right) \pm i\pi\delta(x)[/tex]

But this doesn't seem to give the right hand side of the first equation above. What am I missing?

Thanks in advance!

How does the [itex](\displaystyle{\not}{P} + m)[/itex] appear?
 
It's because P/ - m is a matrix, and so first you have to write 1/(P/ - m) as (P/ + m)/(P2 - m2).

So in detail,

1/(P/ - m + iε) - 1/(P/ - m + iε) = (P/ + m)[1/(P2 - m2 + iε) - 1/(P2 - m2 - iε)]
= (P/ + m)[-iπ δ(P2 - m2) -iπ δ(P2 - m2)] = (P/ + m)(-2iπ δ(P2 - m2))
 
Bill_K said:
It's because P/ - m is a matrix, and so first you have to write 1/(P/ - m) as (P/ + m)/(P2 - m2).

So in detail,

1/(P/ - m + iε) - 1/(P/ - m + iε) = (P/ + m)[1/(P2 - m2 + iε) - 1/(P2 - m2 - iε)]
= (P/ + m)[-iπ δ(P2 - m2) -iπ δ(P2 - m2)] = (P/ + m)(-2iπ δ(P2 - m2))

Thanks BillK, that cleared it up!
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 13 ·
Replies
13
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K