Direct Products of Modules - Bland - Rings and Their Modules

  • Context: Graduate 
  • Thread starter Thread starter Math Amateur
  • Start date Start date
  • Tags Tags
    Modules Rings
Click For Summary
SUMMARY

In Paul E. Bland's book, "Rings and Their Modules," the direct product of a family of modules is defined in Section 2.1, with Proposition 2.1.1 establishing a unique module homomorphism from any R-module N to this direct product. This unique mapping is crucial as it demonstrates the existence of the formally defined direct product and highlights its structural significance in module theory. The re-definition of the direct product following the proposition serves to clarify its properties and applications within the context of R-modules.

PREREQUISITES
  • Understanding of R-modules and their properties
  • Familiarity with module homomorphisms and linear mappings
  • Basic knowledge of direct products and direct sums in algebra
  • Concepts of Proposition and definitions in mathematical literature
NEXT STEPS
  • Study the implications of unique homomorphisms in module theory
  • Explore the properties of direct sums and their relationship to direct products
  • Investigate examples of R-modules and their direct products
  • Review additional literature on module homomorphisms and their applications
USEFUL FOR

Mathematicians, algebraists, and students studying module theory, particularly those interested in the structural aspects of R-modules and their direct products.

Math Amateur
Gold Member
MHB
Messages
3,920
Reaction score
48
I am reading Paul E. Bland's book, Rings and Their Modules.

In Section 2.1: Direct Products and Direct Sums, Bland defines the direct product of a family of modules. He then, in Proposition 2.1.1 shows that there is a unique module homomorphism (or R-Linear mapping) from any particular R-module N to the direct product. He then re-defines the direct product.

My question is - what is going on? Why is Bland doing this?

Can anyone help explain what is going on here? What is the point of demonstrating that there is a unique homomorphism from any module to a given direct product? Further, why would one need to or want to demonstrate that every R-Module maps uniquely onto a direct product? Is this some way to show that the formally defined direct product actually exists? But even then how does the unique homomorphism assure this? What is the motivation for the proposition and the re-definition of the direct product?

Details of Bland's definition, proposition and re-definition follow.

The (first) definition of a direct product of modules is as follows:
attachment.php?attachmentid=69346&stc=1&d=1399102025.jpg

Proposition 2.1.1, preceded by an important definition, is as follows:
attachment.php?attachmentid=69347&stc=1&d=1399118425.jpg

Finally, the following is Bland's re-definition of direct product in the light of Proposition 2.1.1.

attachment.php?attachmentid=69348&stc=1&d=1399118425.jpg


Again, my question is - what is going on here? What is the motivation for Proposition 2.1.1 and what is achieved by the Proposition and the subsequent redefinition?

Hope someone can throw some light on what Bland is doing.

Peter
 

Attachments

  • Bland - Section 2.1 - Definition of a Direct Product of Modules.jpg
    Bland - Section 2.1 - Definition of a Direct Product of Modules.jpg
    72.6 KB · Views: 810
  • Bland - Proposition 2.1.1 - Section 2.1.jpg
    Bland - Proposition 2.1.1 - Section 2.1.jpg
    48.5 KB · Views: 920
  • Bland - Re-Definition of Direct Product of Modules.jpg
    Bland - Re-Definition of Direct Product of Modules.jpg
    47.1 KB · Views: 891
Last edited:
Physics news on Phys.org
I'm sorry you are not generating any responses at the moment. Is there any additional information you can share with us? Any new findings?
 
Thanks for your post Greg ... Still reflecting on this issue ... And hoping someone can help

Really appreciate your thoughts ...

Peter
 

Similar threads

  • · Replies 14 ·
Replies
14
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
Replies
1
Views
1K
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
6
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 9 ·
Replies
9
Views
4K