Which Way Does the Normal Vector in da Point?

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SUMMARY

The discussion focuses on the direction of the normal vector in the context of calculating current using the expression I = ∫_S J · da. Participants agree that the normal vector should face outward, but its direction can vary depending on the specific surface being analyzed. Additionally, when applying Ampère's Law to find the magnetic field at a distance from a wire, it is clarified that the calculation reflects the contribution from the enclosed current, analogous to Gauss's Law. Understanding these concepts is essential for accurate electromagnetic analysis.

PREREQUISITES
  • Understanding of vector calculus and surface integrals
  • Familiarity with Ampère's Law and its applications
  • Knowledge of Gauss's Law and electric fields
  • Basic concepts of current density (J) and magnetic fields
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  • Study the application of Ampère's Law in different geometries
  • Learn about the implications of the normal vector in surface integrals
  • Explore the relationship between current density and magnetic fields
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Niles
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Hi all

I have two questions.

1) We have the following expression for the currect:

I = \int\limits_\mc S {{\bf{J}} \cdot {\rm{d}}{\bf{a}}}

Which way does the normalvector in da point? I think it's very crucial, because I might end up with a negative current if I don't get this right.

2) When I want to find the magnetic field a distance s from a wire, which has a current I going through it, I use Ampére's Law. But when I do this, don't I only find the magnetic field caused by a single "disk" in the wire?


Niles.
 
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I am pretty sure it should be the outward facing normal.
 
Yes, but there's two ends, so it might go either way?
 
Yes... If I have a cylinder that looks like

O---------O

The normal on the left side will be pointing to the left, and the normal on the right side will be pointing to the right.
 
1) depends on what you consider the direction of J.
J is always the direction of the current... So J.da=J* da* cos(theta) will depend on the angle theta

2) its like gauss law..in gauss law..no matter how many charges are present outside, Electric Field on the surface depends on the charge enclosed by the surface only, right?
Similarly here B depends on Ienclosed
 

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