Directional derivatives, SIMPLE

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Homework Help Overview

The discussion revolves around calculating the directional derivative of a function f(x, y, z) = xe^y + ye^z + ze^x at the point (0, 0, 0) using a given directional vector v = <-2, 0, 5>. Participants are exploring the correct application of the gradient and the concept of directional derivatives.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to compute the directional derivative using the gradient at a specific point but questions the correctness of their result. Some participants highlight the importance of using the unit vector derived from the directional vector in the calculation.

Discussion Status

Participants are actively engaging with the problem, with one providing a clarification about the necessity of using the unit vector for the directional derivative. This guidance appears to be helpful for the original poster's understanding.

Contextual Notes

There is an implied assumption that the original poster may not have considered the conversion of the directional vector into a unit vector, which is essential for the calculation of the directional derivative.

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f(x, y, z) = xe^y + ye^z + ze^x, at (0, 0, 0),

directional vector v = <-2, 0, 5>

i solved for gradient f = (e^y + ze^x, xe^y + e^z, ye^z + e^x), at f(0,0,0) to be...

gradient f = (1,1,1)

this would make the answer just be -2 + 0 + 5 = 3
but this isn't right.

can someone show me what i did wrong?
 
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The directional derivative involves the unit vector in the direction of v, not v itself. Find the unit vector u = v/|v| and use that in your calculation.
 
thank you! that makes a lot of sense
 

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