Discharging a capacitor - how long does it take

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Homework Help Overview

The discussion revolves around the discharge of a capacitor with specific parameters: a charge of 1.09 C, a potential difference of 16V, and a capacitance of 68,000 µF. Participants are exploring how long it takes for the capacitor to discharge through leakage current, which is defined as 0.003 µA per µF per V, leading to a maximum leakage current of 3260 µA.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between charge, current, and time, with one participant attempting to use the formula Q=It to find discharge time. Others raise questions about the time constant and the changing nature of the discharge current. Differential equations are introduced, but some express confusion about their necessity and relevance to the problem. There is also discussion about the implications of leakage current and how it varies with voltage.

Discussion Status

The conversation is ongoing, with participants exploring various interpretations of the problem. Some have provided insights into the relationship between current and voltage, while others are questioning the validity of their approaches. There is no explicit consensus, but productive dialogue is occurring regarding the nature of the discharge process and the mathematical relationships involved.

Contextual Notes

Participants note that the problem may not require solving differential equations, as it is a homework question worth only two marks. There is also a recognition that the initial conditions of charge and current are important for the calculations being discussed.

  • #31
jsmith613 said:
just to check though, for a discharging capacitor, is the voltage across the resistor the same as that cross the capacitor BUT the for a charging capacitor the sum of the p.d's across the capacitor and resistor = source (i.e: they are not the same at all points)??

For the typical charging capacitor circuit, the sum of the resistor and capacitor p.d.'s is constant (equal to the voltage source).

attachment.php?attachmentid=48142&stc=1&d=1339167027.gif


Of course, for any complete "tour" around a given circuit the sum of all potential changes must be zero according to Kirchhoff.
 

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  • #32
gneill said:
For the typical charging capacitor circuit, the sum of the resistor and capacitor p.d.'s is constant (equal to the voltage source).

attachment.php?attachmentid=48142&stc=1&d=1339167027.gif

yes...thanks :)

Of course, for any complete "tour" around a given circuit the sum of all potential changes must be zero according to Kirchhoff.

for this I just learn sum of p.d across componenets = emf of source (assuming wire have no resistance / no internal resistance)
 

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