Discontinuity at certain points

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SUMMARY

The discussion focuses on finding two functions, f and g, that are discontinuous at the points of the set {1/n : n a positive integer} ∪ {0} and {1/n : n a positive integer}, respectively, while remaining continuous elsewhere. A proposed solution for f is f(x) = 1 if x = 1/n or x = 0, and f(x) = 0 otherwise, which achieves the desired discontinuities. For g, the suggestion of using the floor function, f(x) = [1/x], introduces a jump discontinuity at 1/n, confirming its non-differentiability at those points.

PREREQUISITES
  • Understanding of continuity and discontinuity in real functions
  • Familiarity with the concept of limits in calculus
  • Knowledge of the floor function and its properties
  • Basic experience with piecewise functions
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  • Research the properties of discontinuous functions in real analysis
  • Study the implications of jump discontinuities on differentiability
  • Explore piecewise function construction techniques
  • Learn about the behavior of the floor function in mathematical contexts
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Mathematics students, particularly those studying real analysis, educators teaching calculus concepts, and anyone interested in the properties of discontinuous functions.

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Homework Statement



1.Find a function f : R → R which is discontinuous at the points of the set
{1/n : n a positive integer} ∪ {0} but is continuous everywhere else.
2. Find a function g : R → R which is discontinuous at the points of the set
{1/n : n a positive integer} but is continuous everywhere else.


Homework Equations





The Attempt at a Solution


I'm thinking of making f(x)=0 at points that f is discontinuous and f(x)=x everywhere else. But that only works for 2, not 1, right? Could anyone give me some hints? I'm not sure what the question is asking for. Thanks!
 
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Why not just f(x)= 1 if x= 1/n for some positive integer n or x= 0, 0 otherwise?
 
only discontinuous..?
try, f(x) =[1/x]...where...[y] is the greatest integer less than or equal to y or as you would call, floor(y)...f(1/n) leads to a jump discontinuity one you can never fix, and hence an implied non-differentiability.
 

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