Discontinuity Help | Get Answers Now

[madeeeeee]

I've attached the page that I need help with
Thank you

 

[LCKurtz]

I would suggest you scan it and post the image here. Many viewers here will not spend the time or take the risk of opening a possibly virus laden word document.

 

[madeeeeee]

But i have it saved in a word document and i don't have a scanner. There is no viruses. I just need help on the question.

 

[micromass]

This actually belongs to the homework help forum... This isn't the place for such a posts.

Now, I'm happy to help you. What did you already try to solve the problems? You can start of by searching in your book what exactly a discontinuity is and what exactly the three different types are. Once you've done that and you still don't know, then come back here...

 

[micromass]

But for now, I can already tell you that those two limits are correct!

 

[madeeeeee]

ok is e correct?
A Jump is when you need to pick your pencil up while your tracing the line. Removable is when there is a hole between a line and Infinite is like having an asymptote but i don't think i need to worry about that one because the graph clearly doesn't have that one. There is also two cusps which means the limit does not exist. my confusion starts with the wording of the questions a and b i just don't understand where i am looking to find the discontinuities and if it wants me to state all of them. how i should state that.

 

[micromass]

First of all, limits do exist in cusps! only derivatives don't.

Now, do you see any jumps on your graph? Try to draw the graph with you pencil, where do you need to lift your pencil up?

 

[madeeeeee]

at x= 0 and x= 3

 

[micromass]

Correct, these are the jumps.

Now the removable singularities, do you see any holes in your functions? Places were the function is not defined?

 

[madeeeeee]

at (0, 4), (3, 2), and (7, -1)

 

[micromass]

Yes, that is the correct answer!

 

[madeeeeee]

sweet, so i get everything now, thanks to you :) but for question a what does it mean when it says find it between (-8, 12) i just don't get that

 

[micromass]

Well, it says that every discontinuity you find must be between -8 and 12. For example, saying that -50 is a discontinuity is not allowed (which makes sense, since you're only given the graph from -9 to 12, so you can't see any othe value).
Just ignore it

 

[madeeeeee]

Thank you so much for your help. I really appreciate it.

 

[madeeeeee]

sorry i need to ask one for thing, were c, d, and e all correct ?

 

[micromass]

d and e are correct. c is not...

 

[madeeeeee]

oh... limit does not exist

 

[micromass]

indeed!