Discover Specific Heat Calculations for Carbon and Unknown Substance

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SUMMARY

The discussion focuses on calculating specific heat energy for carbon and an unknown substance. For carbon, to raise the temperature of 18 kg from -5°C to 17°C, the energy required is calculated using the formula energy = C × m × Δt, resulting in 3.28 kJ. The specific heat capacity (C) for carbon is established at 709 J/kg·K. For the unknown substance, 200 g absorbs 7320 J of energy with a temperature increase from 5°C to 30°C, prompting the need to calculate its specific heat capacity to identify the substance.

PREREQUISITES
  • Understanding of specific heat capacity
  • Familiarity with the formula energy = C × m × Δt
  • Basic knowledge of temperature scales (Celsius)
  • Ability to perform unit conversions (grams to kilograms)
NEXT STEPS
  • Learn how to calculate specific heat capacity for various materials
  • Research the properties of common substances and their specific heat values
  • Study the principles of thermodynamics related to heat transfer
  • Explore practical applications of specific heat calculations in real-world scenarios
USEFUL FOR

Students in physics or chemistry, educators teaching thermodynamics, and professionals in material science or engineering who require knowledge of heat transfer and specific heat calculations.

lynn0808
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a.Determine the amount of energy to raise the temperature of 18 kg of carbon from -5^0C to 17^0C.

B. 200g of a certain substance absorbs 7320 J of energy and experienced a temperature rise from 5^0C to 30^0C. By calcuating its "C" value, identify as near as possible, the unknown substance.


delta t= 17-5=12^0C. M=18kg
C=709j/kg
energy=cXmXdelta t
709J/kg.K X 18kg X12K
energy=3.28 KJ
=3.3 X10^2?

Im not sure what I am doing. Need help
 
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lynn0808 said:
a.Determine the amount of energy to raise the temperature of 18 kg of carbon from -5^0C to 17^0C.

B. 200g of a certain substance absorbs 7320 J of energy and experienced a temperature rise from 5^0C to 30^0C. By calcuating its "C" value, identify as near as possible, the unknown substance.


delta t= 17-5=12^0C. M=18kg
C=709j/kg
energy=cXmXdelta t
709J/kg.K X 18kg X12K
energy=3.28 KJ
=3.3 X10^2?

Im not sure what I am doing. Need help

First seems fine , your same strategy needs to be applied to the second question.
 

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