Calculating Specific Heat: 50g of Unknown Substance at 25°C to 89.7°C

[Jurrasic]

50 grams of a substance absorbed 2.578 kj of energy as it changed from 25 degrees celsius to 89.7
What is the specific heat of the unknown substance in J/gC ?

Is it correct to use :
q = m c delta T

q = specific heat
m = mass
c = ?
delta T here is 64.7

The answer seems really big? Is it :
(50grams) x (2578kj) x (64.7 C ) = answer ?
That seems wrong? Is there a more correct way to do it?

 

[SteamKing]

You've got your quantities confused. q = heat put into or taken away from the substance in Joules. c = specific heat of the substance in J/gC.

 

[Jurrasic]

You've got your quantities confused. q = heat put into or taken away from the substance in Joules. c = specific heat of the substance in J/gC.

LOL oh thanks :)~

Got it working now haha