Discover the Answer to e^(xln(y)) with Quick and Easy Calculations | x = -1.18

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Homework Help Overview

The discussion revolves around the expression e^(xln(y)) and its simplification, particularly with x set to -1.18. The context shifts to solving a logarithmic equation involving t, where various constants are known.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the simplification of e^(xln(y)) and its equivalence to y^x. There is a transition to a more complex logarithmic equation involving t, prompting questions about how to isolate t.

Discussion Status

Some participants have offered guidance on transforming the logarithmic equation, while others express uncertainty about the solvability of the resulting expression. There is an indication that the discussion is progressing, with one participant suggesting they may have resolved their issue.

Contextual Notes

The problem includes known constants and a specific equation format, but the exact values and relationships are not fully detailed, leaving some assumptions under discussion.

eddysd
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What does e^(xln(y)) equal?

EDIT: x being a number, -1.18
 
Last edited:
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e^(xln(y)) = (e^ln(y))^x = y^x

*@hgfalling corrected :)
 
Last edited:
Wait, what?

[tex]e^{x \ln y} = (e^{\ln y})^x = y^x[/tex]
 
ok, thankyou but it actually didn't help, my problem is below:

maCln(t/600)+mbCvln(t/500)=0

Where ma, C, mb and Cv are known, how do I work out t?
 
Make both sides a power of e. But first, turn it into one logarithm.

[tex]a log(x) + b log(y) = log(x^a y^b)[/tex]
 
Doing that gives me:

(t/600)^(26x10^3)x(t/500)^(21.99x10^3)=0

Which doesn't seem solvable to me!

Any ideas?
 
eddysd said:
Doing that gives me:

(t/600)^(26x10^3)x(t/500)^(21.99x10^3)=0

Which doesn't seem solvable to me!

Any ideas?

Try another log rule. Like ln(t/600)=ln(t)-ln(600).
 
Thanks for all the help, think I've got it sorted now!
 

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