matt_747
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If f is an even function on [-a,a] , show that ω(f;[-a,a];δ) = ω(f;[0,a];ε) .
help will be appreciated so much
help will be appreciated so much
The discussion focuses on the relationship between even functions and the modulus of continuity, specifically demonstrating that for an even function f defined on the interval [-a, a], the modulus of continuity ω(f;[-a,a];δ) is equal to ω(f;[0,a];ε). The notation used for the modulus of continuity is clarified as ω(f;[a,b];δ) = sup |f(x)-f(y)| for x, y in [a,b] where |x-y| ≤ δ. This establishes a foundational understanding of how even functions behave in relation to continuity over symmetric intervals.
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