Discovering Exponential Functions: 2 Equations for y=3 with y-intercept of 5

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SUMMARY

The discussion focuses on deriving two equations for an exponential function with a y-intercept of 5 and a horizontal asymptote at y=3. The first equation provided is y=2^(x+1) + 3. To find the second equation, the suggestion is to reflect the graph across the y-axis by replacing "x" with "-x", resulting in the equation y=2^(-x+1) + 3. This method ensures both equations represent the same exponential function with the specified characteristics.

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  • Understanding of exponential functions and their properties
  • Knowledge of y-intercepts and horizontal asymptotes
  • Familiarity with graph transformations, specifically reflections
  • Basic algebra skills for manipulating equations
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  • Learn about graph transformations, including reflections and translations
  • Explore the concept of horizontal asymptotes in exponential functions
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haleym
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I need to write 2 equations that represent the same exponential function with a y-intercept of 5 and an asymptote at y=3. I got y=2^(x+1) + 3 but I don't know how to find the second equation. Can someone please explain this to me. Thanks.
 
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Since the y- intercept is at (0, 5) and the asymptote, y= 3, is symmetric about the x-axis, try "reflecting" that graph in the y-axis. That is, replace your "x" with "-x".
 
Thank you!
 

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