Discovering Patterns in the Difference of Squares Equation

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SUMMARY

This discussion focuses on identifying patterns in the Difference of Squares equation, specifically through the expressions (a+b+c)(a+b-c), (a+b+c)(a-b-c), and (a+b-c)(a-b+c). Participants noted how terms like b+c and b-c compensate for each other, influencing the resulting signs in the equations. The key takeaway is the consistent emergence of the terms 2ab and -2bc, which arise from the interactions of the components in the equations.

PREREQUISITES
  • Understanding of algebraic identities, particularly the Difference of Squares.
  • Familiarity with polynomial expansion techniques.
  • Basic knowledge of mathematical notation and operations.
  • Ability to manipulate and simplify algebraic expressions.
NEXT STEPS
  • Explore advanced algebraic identities, including the Sum and Difference of Cubes.
  • Learn about polynomial factorization methods in algebra.
  • Study the implications of symmetry in algebraic expressions.
  • Investigate the geometric interpretations of algebraic identities.
USEFUL FOR

Students, educators, and mathematicians interested in deepening their understanding of algebraic patterns and identities, particularly those related to the Difference of Squares.

rocomath
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I'm looking for patterns and if you can add to things I noticed before working it out, that would be good :-]

1. (a+b+c)(a+b-c)=a^2+b^2+c^2+2ab

I noticed that b+c and b-c compensated for each other.

2. (a+b+c)(a-b-c)=a^2-b^2-c^2-2bc

a+b and a-b compensated for each other and the fact that it's b+c and -b-c, is the reason that it was -2bc?

3. (a+b-c)(a-b+c)=a^2-b^2-c^2+2bc

a+b and a-b compensated for each other, Now I figured from problem 2 that it would be 2bc again, but I didn't predict the sign correctly?
 
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Not sure I will be helpful here but all I can see is that
rocophysics said:
2. (a+b+c)(a-b-c)=a^2-b^2-c^2-2bc

a+b and a-b compensated for each other and the fact that it's b+c and -b-c, is the reason that it was -2bc?

(a+b+c)(a-b-c)==(a+(b+c))(a-(b+c))=(a)^2-(b+c)^2

and the same for the 3rd one.

for the first one:
<br /> (a+b+c)(a+b-c)((a+b)+c)((a+b)-c)

EDIT: oh wait...that is not what you were talking about...my bad
 
rock.freak667 said:
EDIT: oh wait...that is not what you were talking about...my bad
Nope, lol. But I didn't even think about what you were doing (grouping then putting it in a more visible manner). Thanks, still helped!
 

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