Discrete probability distributions

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 2K views
somecelxis
Messages
121
Reaction score
0

Homework Statement


Here's the question:
Given X is a discrete random variable. E(X-2) = 1/3 , VAR(X-2) = 20/9 .
Detrmine value of E(X^2)
the ans is 23/3 . but i ended up getting 3 . why i am wrong?


Homework Equations





The Attempt at a Solution

 

Attachments

  • DSC_0053[1].jpg
    DSC_0053[1].jpg
    20.4 KB · Views: 439
Physics news on Phys.org
somecelxis said:

Homework Statement


Here's the question:
Given X is a discrete random variable. E(X-2) = 1/3 , VAR(X-2) = 20/9 .
Detrmine value of E(X^2)
the ans is 23/3 . but i ended up getting 3 . why i am wrong?


Homework Equations





The Attempt at a Solution


##\text{Var}(X-2) = \text{Var}(X)## because ##\text{Var}(\cdot)## is unaffected by a non-random shift. Also: ##\text{Var}(X) = E(X^2) - (EX)^2##.
 
somecelxis said:

Homework Statement


Here's the question:
Given X is a discrete random variable. E(X-2) = 1/3 , VAR(X-2) = 20/9 .
Detrmine value of E(X^2)
the ans is 23/3 . but i ended up getting 3 . why i am wrong?

You made a mistake when expanding (x-2)2.

ehild
 
  • Like
Likes   Reactions: 1 person
ehild said:
somecelxis said:

Homework Statement


Here's the question:
Given X is a discrete random variable. E(X-2) = 1/3 , VAR(X-2) = 20/9 .
Detrmine value of E(X^2)
the ans is 23/3 . but i ended up getting 3 . why i am wrong?

You made a mistake when expanding (x-2)2.

ehild

I guess I would have caught that if the OP had typed out his work, but since I never read attached thumbnails I missed it.