Non-Zero Discrete Distributions

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Homework Help Overview

The discussion revolves around discrete random variables, specifically focusing on non-zero adjustments to distributions such as the Binomial and Poisson distributions. The original poster presents a problem that involves deriving properties of a new variable defined from an existing one, under the condition that the variable is non-zero. Participants explore the implications of this adjustment and its effects on probability and statistical measures.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Some participants suggest viewing the problem through the lens of conditional distributions and the definition of a new probability space. Others question whether to apply the actual density functions of the original distributions. There is also discussion about the correct formulation of conditional probabilities and the use of truncated distributions.

Discussion Status

The discussion is active, with participants offering various perspectives on how to approach the problem. There is an ongoing examination of the implications of the non-zero condition and how it affects expected values and variances. Some participants are clarifying concepts while others are questioning assumptions and definitions.

Contextual Notes

Participants note the need to define circumstances under which the adjustment for non-zero values can be considered negligible, prompting a discussion on the practical equivalence of statistical measures in different contexts.

squenshl
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Homework Statement


Suppose we have a discrete random variable whose values $X = x$ can include the value $0$. Some examples are: ##X\sim \text{Binomial}(n,p)## with ##x = 0,1,2,\ldots,n## and ##X\sim \text{Poisson}(\lambda)## with ##x = 0,1,2,3,\ldots## Sometimes we can only observe these variables when ##X = x \neq 0##, i.e. when ##x## is not zero. These distributions are known as the non-zero (adjustments) to the original distributions. For the examples discussed above, they are the Non-Zero Binomial and Non-Zero Poisson respectively. Show that the variable ##Y = x## for ##x \neq 0## has:

1. Probability function ##\text{Pr}(Y=y)=c\text{Pr}(X = x)## for ##x \neq 0## and that ##c = \frac{1}{1-\text{Pr}(X=0)}##.
2. ##E(Y) = cE(X)##.
3. ##\text{Var}(Y) = c\text{Var}(X)+c(1-c)\left((E(X)\right)^2##.
4. With respect to the two non-zero examples above, discuss when this adjustment can be ignored, i.e. it has little impact on the what is actually observed.

Homework Equations


##E(Y) = \sum_{i=1}^{n} y_i \text{Pr}(Y=y)##.
##\text{Var}(Y) = E(Y^2)-E(Y)^2##.

The Attempt at a Solution


I'm not actually sure what they are trying to for 1. 2. and 3. Do we have to apply the actual density functions of the 2 respective distributions above or what?
 
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There are a couple of ways you could look at this. One is as a conditional distribution: replace
$$E(\textrm{some expression involving }Y),\ Var(\textrm{some expression involving }Y),\ Pr(\textrm{some expression involving }Y)$$
by
$$E(\textrm{some expression involving }X|X\neq 0),\ Var(\textrm{some expression involving }X|X\neq 0),\ Pr(\textrm{some expression involving }X|X\neq 0)$$
respectively.

The other is to define a new probability space. If the original probability space is ##(\{0,1,...\},\Sigma, P)## then define a new space ##(\{1,2,...\},\Sigma', P')## such that, for ##A\subseteq \mathbb{N}-\{0\}##, ##P'(A)=\frac{P(A)}{1-P(\{0\})}## and ##\Sigma'=\{S-\{0\}\ |\ S\in\Sigma\}##. Then we can define ##Y## as the restriction of ##X## to ##\{1,2,...\}##.

It's probably easier to go with the first one.
 
andrewkirk said:
There are a couple of ways you could look at this. One is as a conditional distribution: replace
$$E(\textrm{some expression involving }Y),\ Var(\textrm{some expression involving }Y),\ Pr(\textrm{some expression involving }Y)$$
by
$$E(\textrm{some expression involving }X|X\neq 0),\ Var(\textrm{some expression involving }X|X\neq 0),\ Pr(\textrm{some expression involving }X|X\neq 0)$$
respectively.

The other is to define a new probability space. If the original probability space is ##(\{0,1,...\},\Sigma, P)## then define a new space ##(\{1,2,...\},\Sigma', P')## such that, for ##A\subseteq \mathbb{N}-\{0\}##, ##P'(A)=\frac{P(A)}{1-P(\{0\})}## and ##\Sigma'=\{S-\{0\}\ |\ S\in\Sigma\}##. Then we can define ##Y## as the restriction of ##X## to ##\{1,2,...\}##.

It's probably easier to go with the first one.
Oh right so ##Pr(\textrm{some expression involving }X|X\neq 0) = 1-Pr(X=0)##.
 
squenshl said:
Oh right so ##Pr(\textrm{some expression involving }X|X\neq 0) = 1-Pr(X=0)##.

NO, NO, NO!
P({\cal A} | X \neq 0)
is given by the usual conditional probability formula, which you should know thoroughly by now.
 
Ray Vickson said:
NO, NO, NO!
P({\cal A} | X \neq 0)
is given by the usual conditional probability formula, which you should know thoroughly by now.

So ##P({\cal A} | X \neq 0) = \frac{P({\cal A} \cap X \neq 0)}{P(X \neq 0)}##. Can we use a truncated distribution via ##f(x|X>0) = \frac{g(x)}{1-F(0)}## where ##g(x) = f(x)## for all ##x>0## and ##g(x) = 0## everywhere else and ##F(x)## is the CDF?
 
squenshl said:
So ##P({\cal A} | X \neq 0) = \frac{P({\cal A} \cap X \neq 0)}{P(X \neq 0)}##. Can we use a truncated distribution via ##f(x|X>0) = \frac{g(x)}{1-F(0)}## where ##g(x) = f(x)## for all ##x>0## and ##g(x) = 0## everywhere else and ##F(x)## is the CDF?

You tell me.
 
How about part 4. With respect to the two non-zero examples above, discuss when this adjustment can be ignored, i.e. it has little impact on the what is actually observed.

Are they asking for an example in which ##x=0## is included?
 
squenshl said:
How about part 4. With respect to the two non-zero examples above, discuss when this adjustment can be ignored, i.e. it has little impact on the what is actually observed.

Are they asking for an example in which ##x=0## is included?

No. They seem to be asking for circumstances wherein ##E(X|X \neq 0)##, ##\text{Var}\,(X|X \neq 0)## and maybe ##P({\cal A}|X \neq 0)## are almost the same as ##EX##, ##\text{Var}\,X## and ##P({\cal A})##. I think they want you to define "almost the same", for practical purposes.
 

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