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## Main Question or Discussion Point

**discrete spacetime means discrete momentum ??**

the question is using De Broglie's Wavelength [tex] \lambda = h|p|^{-1} [/tex]

then in case space is discrete would mean that there is a minimum possible wavelength in nature , for example [tex] \lambda = k l_{p} [/tex] for Planck's lenght this would mean that the maximum allowed momentum modulus would be [tex] h(k l_{p})^{-1} [/tex] for 'k' a constant , then since momentum is finite and spacetime is also finite there wouldn't be any IR or UV divergences but does this make sense