Discrete Time Fourier Transform

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SUMMARY

The discussion focuses on calculating the Discrete Time Fourier Transform (DTFT) of the sequence h[n] = (-1)^{n} \frac{\sin(\frac{\pi}{2}n)}{\sin(\pi n)}. Participants highlight the useful property that the product of two sequences in the time domain corresponds to the convolution of their DTFTs in the frequency domain, expressed as x[n]y[n] --> X[Ω]*Y[Ω]. Additionally, the transformation of the sinc function is noted, where \frac{\sin(\frac{\pi}{2}n)}{\sin(\pi n)} results in a rectangular function rect[\frac{2Ω}{\pi}]. Concerns are raised regarding the convergence of the DTFT due to the alternating factor (-1)^{n} in the sequence.

PREREQUISITES
  • Understanding of Discrete Time Fourier Transform (DTFT)
  • Familiarity with properties of Fourier transforms
  • Knowledge of sinc functions and their properties
  • Basic concepts of convergence in signal processing
NEXT STEPS
  • Study the convergence criteria for DTFTs of sequences with alternating signs
  • Explore the properties of the sinc function and its applications in signal processing
  • Learn about the convolution theorem in the context of Fourier transforms
  • Investigate the implications of rectangular functions in frequency analysis
USEFUL FOR

Signal processing engineers, students studying Fourier analysis, and anyone involved in digital signal processing who seeks to understand the DTFT and its properties.

Mr.Tibbs
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Find the DTFT of:

h[n]=(-1)^{n}\frac{sin(\frac{\pi}{2}n}{sin(\pi n}

useful properties:

x[n]y[n] --> X[Ω]*Y[Ω]

\frac{sin(\frac{\pi}{2}n}{sin(\pi n} --> rect[\frac{2Ω}{\pi}


I have no clue how to deal with the (-1)^{n}[\itex] the DTFT of that doesn&#039;t converge. . .<br /> <br /> any help would be appreciated
 
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Mr.Tibbs said:
I have no clue how to deal with the (-1)^{n}[\itex] the DTFT of that doesn&#039;t converge. . .
<br /> Why do you say that?
 

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