Solving for the Real and Imaginary Number

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SUMMARY

The discussion centers on finding the 4th coefficient in a discrete time Fourier Series for a real-valued periodic sequence, specifically for the coefficients a_k = {3, 1-2j, -1, ?}. The user attempts to derive the missing coefficient a_3 using the equation involving complex exponentials and trigonometric identities. The confusion arises from ensuring the resulting function remains real-valued, highlighting the necessity for the coefficients to satisfy the condition of complex conjugates for a purely real signal. The user suggests that additional information may be required to fully resolve the problem.

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Homework Statement



Find the 4th Coefficient in a sample of 4 discrete time Fourier Series coefficients in a real time valued periodic sequence. k = 0,1,2,3

a_k = {3, 1-2j, -1, ?}

Homework Equations



upload_2019-2-19_13-20-48.png


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The Attempt at a Solution



Step 1: (1-2j)e^(j*.5pi*n) +a_3 e ^ -(j*.5pi*n) + 3 + (-1)^(n+1)

Step 2: [(1-2j)(cos (pi/2)n + j sin (pi/2)n) + a_3 (cos (pi/2)n)-j sin (pi/2)n]

Solving for a_3 in the final step is where I am confused.
 

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I had a lot of experience with such things and the question doesn't seem to be fully formed to me. Perhaps there is some extra info somewhere? Perhaps the solution revolves around making sure that the resulting function will be real valued as stated in question. That sets constraints between coefficients.
However only summing over positive k values Will make it imposible to get a purely real signal. Normally that would happen when a(-k) is the complex conjugate of a(k). Or should it be using a discrete Fourier sin series, summing over real basis functions rather tan over exp(ikx) complex functions? Though you wouldn't need complex coeffs in that case. Need to see the full question I think.
 
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