Displacement of a wave: Understanding Negative Results

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The discussion revolves around the misunderstanding of wave displacement in the equation y = 0.26 sin(πt − 3.7πx). The user expected a positive result when calculating displacement for specific values of t and x but consistently received a negative value. It was clarified that displacement can indeed be negative, as it represents the vertical position of the wave, not its movement direction. Additionally, the user realized they had incorrectly performed calculations in degrees instead of radians, contributing to the confusion. This highlights the importance of understanding wave properties and the correct use of units in calculations.
BOAS
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Hi,

I don't understand why I keep getting a negative result...

Homework Statement



The displacement (in metres) of a wave is given according to

y = 0.26 sin(πt − 3.7πx),

where t is in seconds and x is in metres,

What is the displacement y when t = 38 and x = 13 [m] ?

Homework Equations





The Attempt at a Solution



The wave travels in the +x direction because as time increases so does the displacement, so I'm expecting a +ve result.

y = 0.26 \sin (\pi 38 - 3.7 \pi 13)

This keeps giving me y = -0.1367 as an answer which surely can't be correct.

I don't know what I'm doing wrong...

Thanks,

BOAS
 
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You seem to be misunderstanding the word "displacement". A wave moves up and down as it travels. It is, as you have calculated, the y coordinate, not movement in the x direction. It certainly can be negative.
 
HallsofIvy said:
You seem to be misunderstanding the word "displacement". A wave moves up and down as it travels. It is, as you have calculated, the y coordinate, not movement in the x direction. It certainly can be negative.

You're right, I had misunderstood that - Thanks, it makes more sense now.

I also did the calculation in degrees which explains why the magnitude of my answer was wrong.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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