Two runners start simultaneously from the same point on a circular 200-m track and run in the opposite direction. One runs at a constant speed of 6.20 m/s, and the other runs at a constant speed of 5.50 m/s. when they meet, (a) for how long a time will they have been running, and (b) how far will each one have run along the track?
The Attempt at a Solution
I could picture exactly what they our describing but I can't get the solution.
(a)When they first meet how long a time will each one have run along the track
(b)How far will each one have run along the track
*I graphed this and found the answer but I want to know if anyone could find a faster way to solving this?
(a) 17 seconds
(b) 106m , 96m
-start = 0, finish = 200m
*track is circular.
*One runner is going in a negative direction
runner 1 average velocity = 6.20m/s
runner 2 average velocity = 5.50m/s
Average Velocity = x2 - x1 / t2 - t1
where x1 is the initial position, x2 is the ending position and t1 is initial time, t2 is ending time.