DISPLACEMENT-TIME graphs question

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To find the total distance traveled in 9 seconds using a displacement-time graph, one must calculate the distance for each segment defined by the coordinates. The segments are from (0,0) to (3,-3), (3,-3) to (5,-3), and (5,-3) to (9,5). The distance for each section can be determined by the absolute change in displacement, which results in 3 meters for the first segment, 0 meters for the second, and 8 meters for the third. Adding these distances together gives a total distance of 11 meters traveled in 9 seconds. Understanding the relationship between displacement and distance is crucial for accurate calculations.
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1. It's a displacement time graph with coordinates (0,0), (3,-3),(5,-3), (9,5) The lines are all linear.
The question first asks 'Calculate the velocity for each section 0-3s, 3-5s,5-9s. I know how to do that part (it's -1m/s, 0m/s, and 2m/s).
But the other part of the question asks: What distance has been traveled in 9s?
How can I find the distance traveled in the total 9 seconds with a displacement/time graph??
(By the way, displacement is the y-axis, time is the x-axis)
 
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I'm sure you know this equation
v=\frac{d}{t}
and just do it in sections
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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