DISPLACEMENT-TIME graphs question

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The discussion focuses on calculating distance traveled using a displacement-time graph with coordinates (0,0), (3,-3), (5,-3), and (9,5). The velocities for the segments 0-3 seconds, 3-5 seconds, and 5-9 seconds are confirmed as -1 m/s, 0 m/s, and 2 m/s, respectively. To find the total distance traveled in 9 seconds, one must consider the absolute values of the displacement changes across each segment, leading to a total distance of 12 meters.

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Rasofia
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1. It's a displacement time graph with coordinates (0,0), (3,-3),(5,-3), (9,5) The lines are all linear.
The question first asks 'Calculate the velocity for each section 0-3s, 3-5s,5-9s. I know how to do that part (it's -1m/s, 0m/s, and 2m/s).
But the other part of the question asks: What distance has been traveled in 9s?
How can I find the distance traveled in the total 9 seconds with a displacement/time graph??
(By the way, displacement is the y-axis, time is the x-axis)
 
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I'm sure you know this equation
v=\frac{d}{t}
and just do it in sections
 

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