DISPLACEMENT-TIME graphs question

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To find the total distance traveled in 9 seconds using a displacement-time graph, one must calculate the distance for each segment defined by the coordinates. The segments are from (0,0) to (3,-3), (3,-3) to (5,-3), and (5,-3) to (9,5). The distance for each section can be determined by the absolute change in displacement, which results in 3 meters for the first segment, 0 meters for the second, and 8 meters for the third. Adding these distances together gives a total distance of 11 meters traveled in 9 seconds. Understanding the relationship between displacement and distance is crucial for accurate calculations.
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1. It's a displacement time graph with coordinates (0,0), (3,-3),(5,-3), (9,5) The lines are all linear.
The question first asks 'Calculate the velocity for each section 0-3s, 3-5s,5-9s. I know how to do that part (it's -1m/s, 0m/s, and 2m/s).
But the other part of the question asks: What distance has been traveled in 9s?
How can I find the distance traveled in the total 9 seconds with a displacement/time graph??
(By the way, displacement is the y-axis, time is the x-axis)
 
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I'm sure you know this equation
v=\frac{d}{t}
and just do it in sections
 
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