Distance and time between 2 train stations

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Homework Help Overview

The problem involves a light-rail train traveling between two stations, where it accelerates, moves at a constant speed, and then decelerates to a stop. The key questions are about calculating the total distance between the stations and the time taken for the journey.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss using kinematic equations to find velocity and distance, with some uncertainty about the stopping distance calculation. There are questions about the accuracy of initial distance calculations and the application of formulas.

Discussion Status

Some participants are providing feedback on calculations, indicating potential errors in the initial distance estimates. There is an ongoing exploration of the correct approach to the problem, with some guidance being offered regarding the formulas used.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can use or the methods they can apply. There is a noted confusion about the factors involved in the calculations.

sktgurl930
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Homework Statement


A light-rail train going from one station to the next on a straight section of track accelerates from rest at 2.27 m/s2 for 15.7 s/ It then proceeds at constant speed for 1346 m before slowing down at 2.2 m/s2 until it stops at the station. What is the distance between the stations? and How much time does it take the train to go between the stations?

Homework Equations


I figured if i used A=v/t i could get v which i could plug into V=x/t and then get X being the distance in the start and then the distance in the middle would just be 1346 since it was given . having trouble figuring out how to get the last one

and for the time
i would think to use Δt=Δv/a

The Attempt at a Solution


ok so i got V= 35.639, and X to equal 559.5323
would the formula to find the stopping distance be Vf^2-Vi^2/2*(-2.2)?
 
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sktgurl930 said:

Homework Statement


A light-rail train going from one station to the next on a straight section of track accelerates from rest at 2.27 m/s2 for 15.7 s/ It then proceeds at constant speed for 1346 m before slowing down at 2.2 m/s2 until it stops at the station. What is the distance between the stations? and How much time does it take the train to go between the stations?

Homework Equations


I figured if i used A=v/t i could get v which i could plug into V=x/t and then get X being the distance in the start and then the distance in the middle would just be 1346 since it was given . having trouble figuring out how to get the last one

and for the time
i would think to use Δt=Δv/a

The Attempt at a Solution


ok so i got V= 35.639, and X to equal 559.5323
would the formula to find the stopping distance be Vf^2-Vi^2/2*(-2.2)?

Yes. Looks like you are on the right track.

I think your first distance is off though by a factor of 2.
 
for my distance i get 2194.2001 m
and they said it was wrong so where do you think i went wrong??
 
sktgurl930 said:
for my distance i get 2194.2001 m
and they said it was wrong so where do you think i went wrong??

I think your first distance is off though by a factor of 2. Did you catch my quick edit?
 
lol no but thanks for helping me out ur really good at this
i got it now


Thank u soo much :smile:
 
sktgurl930 said:
lol no but thanks for helping me out ur really good at this
i got it now


Thank u soo much :smile:

Happy to help.
 

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