Distance between 2 axis in Parallel Axis Theorem

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Homework Help Overview

The discussion revolves around the moment of inertia of a rectangular metal sheet when considering different axes, specifically through a corner versus the center of mass. The original poster seeks to understand the derivation of a specific distance formula related to the Parallel Axis Theorem.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between the dimensions of the sheet and the distance between different axes. There is a focus on understanding how the distance D is calculated and its dependence on the dimensions a and b.

Discussion Status

Participants are actively questioning the assumptions made about the center of mass and the distances involved. Some guidance has been provided regarding the interpretation of distances in relation to the axes, and there is acknowledgment of helpful contributions from other members.

Contextual Notes

There is some confusion regarding the definitions of axes in relation to the dimensions of the plate, as well as the application of the Pythagorean theorem to find distances. The original poster expresses uncertainty about the formula D = (a^2/2^2 + b^2/2^2) and its derivation.

Sunbodi
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Homework Statement


The moment of inertia for a perpendicular axis through the center of a uniform, thin, rectangular metal sheet with sides a and b is (1/12)M(a2 + b2). What is the moment of inertia if the axis is through a corner?

The answer is given as this was a powerpoint lecture and it is: I = 1/3 M(a^2 + b^2)
I'm not looking for how to solve the whole thing however as the moment of Inertia is given in the context of the problem. I'm trying to understand how D was found to be: (a^2/2^2 + b^2 /2^2).

Homework Equations


I = I (cm) + Md^2

The Attempt at a Solution


D is meant to be the distance between the the new axis and the center of mass, if I personally were to solve this I'd state that the center of mass is half the distance between the axis that contains a and the axis that contains b. If that's the case, the distance from the center of mass to a diagonal would be a^2 + b^2 because you're increasing both a and b values by the same distance it originally was from the center of mass.
 
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For clarification: You're trying to understand how the distance between two different axis on a sheet depends on the lengths of the sheet?

I'm asking cause I see questions, but then answers to those questions in later sentences.
 
RomegaPRogRess said:
For clarification: You're trying to understand how the distance between two different axis on a sheet depends on the lengths of the sheet?

I'm asking cause I see questions, but then answers to those questions in later sentences.
I trying to understand why D = (a^2/2^2 + b^2 /2^2). To me it seems as if it should simply be D = (a^2 + b^2)
 
Sunbodi said:
the center of mass is half the distance between the axis that contains a and the axis that contains b
a and b are the dimensions of the plate. In what sense does an axis contain them?
Sunbodi said:
the distance from the center of mass to a diagonal
The distance from the centre to a diagonal is zero. You want the distance to a corner.
It's a/2 parallel to one axis, then b/2 parallel to the other. What does Pythagoras have to say on the matter?
 
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haruspex said:
a and b are the dimensions of the plate. In what sense does an axis contain them?

The distance from the centre to a diagonal is zero. You want the distance to a corner.
It's a/2 parallel to one axis, then b/2 parallel to the other. What does Pythagoras have to say on the matter?

Thank you so much! The second part of your comment really helped me. I've noticed how you're consistently on this forums helping out people whether it comes to high level physics or high school stuff and it's really well appreciated.
 
Sunbodi said:
Thank you so much! The second part of your comment really helped me. I've noticed how you're consistently on this forums helping out people whether it comes to high level physics or high school stuff and it's really well appreciated.
You are welcome.
 

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