Distance between Isotopes in a mass spec

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SUMMARY

The forum discussion centers on calculating the distance between adjacent lines formed by isotopes of krypton (82Kr, 84Kr, and 86Kr) in a mass spectrometer. The electric field is 1.89×104 V/m and the magnetic field is 0.668 T. The calculated radii for the isotopes are 0.0360 m for 82Kr, 0.0369 m for 84Kr, and 0.0378 m for 86Kr. The distance between adjacent lines is determined by the difference in radii, specifically calculated as 2 times the difference between the radii of 84Kr and 82Kr, resulting in a spacing of 0.9 mm.

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Elvis 123456789
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Homework Statement


Suppose the electric field between the plates P and P' in the mass spectrometer in following figure is 1.89×104V/m and the magnetic field in both regions is 0.668 T.

If the source contains the three isotopes of krypton, 82Kr,84Kr, and 86Kr, and the ions are singly charged, find the distance between the two adjaicent lines formed by the three isotopes on the photographic plate. Assume the atomic masses of the isotopes (in atomic mass units) are equal to their mass numbers, 82, 84, and 86. (One atomic mass unit = 1u = 1.66×10−27kg.)

Homework Equations


v = E/B

R = mv/qB

The Attempt at a Solution



I found that the selected speed (v) is 2.83 * 10^4 m/s

I got 0.0360 m for the radius of 82Kr

0.0369 m for 84Kr

and 0.0378 m for 86Kr.

My problem is that I don't even understand what it is that they are asking for. What are these adjacent lines that they are talking about? and if there's three isotopes, shouldn't there be three lines?
 
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You haven't included the image so I can't be certain, but usually the ions that are selected will follow circular arcs of radii that depend upon their mass before they impact on a target. Where they impact they produce an image, either a spot or line depending upon details of the equipment. Presumably they are looking for the distance separating such individual lines. If it turns out that the spacing is even, then any two adjacent lines will do. Perhaps the problem text should have read, "...find the distance between the two adjacent lines formed by the three isotopes..."
 
gneill said:
You haven't included the image so I can't be certain, but usually the ions that are selected will follow circular arcs of radii that depend upon their mass before they impact on a target. Where they impact they produce an image, either a spot or line depending upon details of the equipment. Presumably they are looking for the distance separating such individual lines. If it turns out that the spacing is even, then any two adjacent lines will do. Perhaps the problem text should have read, "...find the distance between the two adjacent lines formed by the three isotopes..."
sorry I forgot about the image.

https://session.masteringphysics.com/problemAsset/1266175/5/22.jpg
gneill said:
You haven't included the image so I can't be certain, but usually the ions that are selected will follow circular arcs of radii that depend upon their mass before they impact on a target. Where they impact they produce an image, either a spot or line depending upon details of the equipment. Presumably they are looking for the distance separating such individual lines. If it turns out that the spacing is even, then any two adjacent lines will do. Perhaps the problem text should have read, "...find the distance between the two adjacent lines formed by the three isotopes..."
Sorry I forgot about the picture.
 

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Okay, it looks like I was correct; You want to find the distance between adjacent impact locations on the particle detector target.
 
Wouldn't that be the difference in radii between two adjacent isotopes? For instance, (Radius for 84Kr) - (Radius for 82Kr) = 0.9 mm?
 
Elvis 123456789 said:
Wouldn't that be the difference in radii between two adjacent isotopes? For instance, (Radius for 84Kr) - (Radius for 82Kr) = 0.9 mm?
Examine the diagram carefully. How far from the selector exit port do the ions land? Is it one radius away?
 
gneill said:
Examine the diagram carefully. How far from the selector exit port do the ions land? Is it one radius away?
ah I see, they all land one diameter away. so 2*[(Radius of 84Kr) - (Radius of 82Kr)]?
 
Elvis 123456789 said:
ah I see, they all land one diameter away. so 2*[(Radius of 84Kr) - (Radius of 82Kr)]?
Sure.
 
gneill said:
Sure.
Ok awesome, thank you kind sir.
 

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